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學習快評丨qibao666888　　蛋??(dan)白??(bai)質??(zhi)是??(shi)由??(you)20種??(zhong)氨??(an)基??(ji)酸?(suan)組??(zu)成??(cheng)的??(de)一??(yi)條??(tiao)高??(gao)分??(fen)子??(zi)鏈秘(lian)??，這??(zhe)個??(ge)高??(gao)分??(fen)子??(zi)鏈??(lian)會??(hui)扭??(niu)曲??(qu)并??(bing)折??(zhe)疊??(die)成??(cheng)獨?(du)特?(te)的??(de)三??(san)維??(wei)結??(jie)構??(gou)??，正??(zheng)是??(shi)這??(zhe)種??(zhong)獨??(du)特??(te)結??(jie)構??(gou)賦??(fu)予??(yu)了??(le)特?(te)定??(ding)蛋??(dan)白??(bai)質??(zhi)的??(de)生??(sheng)物??(wu)功??(gong)能??(neng)?。??要??(yao)設??(she)計??(ji)出??(chu)一??(yi)款??(kuan)成??(cheng)功??(gong)的?(de)蛋?(dan)白??(bai)質?(zhi)產??(chan)品??(pin)??，不??(bu)能??(neng)只??(zhi)關??(guan)注??(zhu)它??(ta)的??(de)三??(san)維??(wei)結??(jie)構??(gou)??，而??(er)是??(shi)要??(yao)能??(neng)成??(cheng)功??(gong)預??(yu)測??(ce)和??(he)設??(she)計??(ji)它??(ta)的??(de)功??(gong)能??(neng)?。洪??(hong)亮??(liang)團??(tuan)隊??(dui)直??(zhi)接??(jie)瞄??(miao)準?(zhun)“功??(gong)能??(neng)預??(yu)測??(ce)”這??(zhe)一??(yi)終??(zhong)極??(ji)目??(mu)標??(biao)??，將??(jiang)復??(fu)雜??(za)的??(de)蛋??(dan)白?(bai)質??(zhi)設??(she)計??(ji)變??(bian)成??(cheng)以??(yi)需??(xu)求??(qiu)為??(wei)導?(dao)向??(xiang)??，配??(pei)合??(he)少??(shao)量??(liang)實??(shi)驗??(yan)輸??(shu)出?(chu)結??(jie)果??(guo)的?(de)簡??(jian)單??(dan)過??(guo)程??(cheng)??！　〉??(dan)白??(bai)質??(zhi)是??(shi)由??(you)氨??(an)基??(ji)酸??(suan)序??(xu)列??(lie)構??(gou)成??(cheng)的??(de)??，氨??(an)基??(ji)酸??(suan)序??(xu)列??(lie)的?(de)長?(chang)度??(du)從??(cong)數??(shu)百??(bai)個??(ge)到??(dao)上??(shang)千??(qian)個??(ge)不??(bu)等??(deng)??。??AI時??(shi)代??(dai)??，數??(shu)據??(ju)是??(shi)推??(tui)動??(dong)技??(ji)術??(shu)進??(jin)步??(bu)的??(de)核??(he)心??(xin)資?(zi)源??(yuan)??，龐??(pang)大??(da)的??(de)蛋??(dan)白??(bai)質??(zhi)序??(xu)列??(lie)數??(shu)據??(ju)集??(ji)能??(neng)幫??(bang)助??(zhu)模??(mo)型??(xing)更??(geng)好?(hao)地??(di)理??(li)解??(jie)蛋??(dan)白??(bai)質??(zhi)的??(de)序??(xu)列??(lie)、結??(jie)構?(gou)和??(he)功??(gong)能??(neng)關??(guan)系??(xi)??。洪?(hong)亮??(liang)團??(tuan)隊??(dui)建??(jian)立?(li)的??(de)蛋??(dan)白??(bai)質??(zhi)序??(xu)列??(lie)數?(shu)據??(ju)集??(ji)Venus-Pod(Venus-Protein Outsize Dataset)含??(han)有??(you)近??(jin)90億??(yi)條??(tiao)蛋??(dan)白??(bai)質??(zhi)序??(xu)列??(lie)??，包??(bao)含??(han)數??(shu)億??(yi)個??(ge)功?(gong)能??(neng)標??(biao)簽??(qian)??，是??(shi)全??(quan)球??(qiu)數??(shu)據??(ju)規(guī)??(gui)模??(mo)最?(zui)大??(da)、功??(gong)能??(neng)批??(pi)注??(zhu)標??(biao)簽??(qian)最??(zui)多??(duo)的?(de)數??(shu)據??(ju)集??(ji)??，也?(ye)是??(shi)另??(ling)一??(yi)行??(xing)業(yè)??(ye)知??(zhi)名??(ming)模??(mo)型??(xing)——美??(mei)國?(guo)ESM-C模??(mo)型?(xing)訓??(xun)練?(lian)用??(yong)的??(de)21億??(yi)蛋??(dan)白?(bai)質?(zhi)序??(xu)列??(lie)的??(de)4倍?(bei)體??(ti)量??(liang)??。。